If you are not sure if I can write simple code here is my FizzBuzz c++ solution:
#include <iostream> using namespace std; int main() { for (int i = 1; i < 101; ++i) { if (i % 3 == 0 && i % 5 == 0) cout << "FizzBuzz"; else if (i % 3 == 0) cout << "Fizz"; else if (i % 5 == 0) cout << "Buzz"; else cout << i; cout << endl; } }
And the output for the first 15 values:
1 2 Fizz 4 Buzz Fizz 7 8 Fizz Buzz 11 Fizz 13 14 FizzBuzz
I guess this proves that I probably am compulsive problem solver. In my defence I was pointing someone else at the idea behind FizzBuzz and I couldn't resist to put down a few lines of code that produced the desired output ...
Posts
Um, the actual game involves substituting "fizz", "buzz" and "fizzbuzz" for the numbers in the proper places, not adding them.
ReplyDeleteHere:
int main()
{
bool flag;
for (int i = 1; i < 101; ++i)
{
flag = true;
if (i % 3 == 0)
{
cout << "Fizz";
flag = False;
}
if (i % 5 == 0)
{
cout << "Buzz";
flag=False;
}
if (flag == True)
{
cout << i << " ";
}
cout << endl;
}
}
That fixes your code. It uses a flag to note if fizz or buzz was written and, if not, writes the integer.
An alternative is to test for mod 3 or mod 5 all at once (i.e. i%3==0||i%5==0 or even (i%3)*(i%5)==0). I think flipping a bit is more elegent than performing redundant math, but that is just my opinion.
I tried to be smart and show the index numbers to confirm that it shows the text at correct positions. But after double checking the original task I admit the index numbers should be replaced. Example updated. Thanks for pointing it out. Have fun :)
ReplyDeleteMy solution:
ReplyDelete#include
using namespace std;
int main(){
int x = 0;
for(x= 1; x<50; ++x){
if (x % 3 == 0){
cout <<"fizz";
}
if (x % 5 == 0){
cout <<"buzz";
}
if(x % 3 != 0 && x % 5 != 0){
cout <<x;
}
cout <<endl;
}
}